发布网友 发布时间:2024-10-18 06:55
共1个回答
热心网友 时间:2分钟前
du = ∂f/∂x dx + ∂f/∂y dy + ∂f/∂z dz..............(1)
dz = ∂z/∂x dx + ∂z/∂y dy...........................(2)
将(2)代入(1):
du = [∂f/∂x + (1+x)/(1+z)e^(x-z)]dx +
+ [∂f/∂y + (1+y)/(1+z)e^(y-z)]dy.......(3)